What is the freezing point of a 0.321m aqueous solution of nacl?

A solution exhibits colligative properties since solute interferes with the interaction of the atoms which would change certain properties of the solution. In this case, it is the freezing point that is affected. We calculate as follows:

ΔT = kf (m) i
       where kf is the freezing point depression constant which is 1.86 for                            water
                   m is molality 
                    i is the van't hoff factor which is 2 for NaCl

ΔT = 1.86(0.321) 2
ΔT = 1.19412 °C
1.19412 °C = 0 - T
T = -1.19412 °C

Ethene molecular fórmula= c2h4molecular weight = 29.046g/molhope it : )