Chemistry, 29.08.2019 01:00 smartypants02

1. compared to carbon-14, what does the nuclide carbon-12 have less of?
a. protons
b. nuetrons
c. energy levels
d. bonding configurtions
what would happen if carbon-14 gained 1 proton and lost 1 nuetron?
a. it would stay carbon-14
b. it would become carbon-13
c. it would become nitrogen-14
d. it would become nitrogen-13
what would happen if bismuth-208 lost 1 proton and gianed 1 nuetron?
a. it would become lead-207
b. it would become lead-208
c. it would become bismuth-207
d. it would stay bismuth-208
the nucleus of an atom has
a. only protons
b. only nuetrons
c. protons and nuetrons
d. protons, nuetrons, and electrons

Answers: 2

Show answers

Answers

Answer from: hdwoody2002

1. energy levels
2. it would stay carbon-14
3. it would become lead-107
4. protons,nuetrons,electrons

Answer from: Quest

The following is a blank kkkxxx idk ttyl

Answer from: Quest

the missing options are :

(1) lower boiling point and a lower freezing point(2) lower boiling point and a higher freezing point(3) higher boiling point and a lower freezing point(4) higher boiling point and a higher freezing point

answer : the correct answer is option (3) higher boiling point and a lower freezing point

explanation :

when a non volatile solute is added to a solvent like water, it results in elevation of boiling point.

let us find the increase in boiling point of water when cacl₂ is added to water to make a solution of 1 m

step 1 : find molality of the solution

let us assume we have 1 l of solution.

$m = \frac{moles (solute)}{l ( solution)}$

$1 m = \frac{moles (cacl_{2})}{1 l }= 1 mol cacl_{2}$

let us convert this to grams of cacl₂.

molar mass of cacl2 is 111 g/mol

grams of cacl₂ = $1 mol \times \frac{111g}{mol} = 111 g cacl_{2}$

mass of solute = 111 g

assuming density of solution same as water which is 1g/ml we have ,

mass of solution = density * volume

mass of solution = $\frac{1g}{ml} \times 1000 ml = 1000 g$

mass of solution = mass of solvent + mass of solute

mass of solute = 1000g - 111g

mass of solute 889 g = 0.889 kg

the molality of the solution can be calculated as

$molality = \frac{mol (solute)}{kg ( solvent)}$

$molality = \frac{1mol}{0.889kg}$

molality = 1.12 m

step 2 : find boiling point elevation.

the elevation in boiling point is calculated as

$\bigtriangleup t_{b} = i \times k_{b} \times m$

here δtb = boiling point elevation

i = vant hoff factor which is the number of ions formed by the solute .

cacl₂ dissociates as $cacl_{2} \rightarrow ca^{2+} + 2 cl^{-}$

it forms 3 ions . therefore,

i = 3

m = molality which is 1.12 m

kb is constant for a given solvent. for water it is 0.512

$\bigtriangleup t_{b} = 3 \times 0.512 \times 1.12$

$\bigtriangleup t_{b} = 1.7$

the boiling point of water increases by 1.7 °c

step 3: find freezing point depression.

when a non volatile solute is added to water, it results in decrease in freezing point.

the formula to find freezing point depression is

$\bigtriangleup t_{f} = i \times k_{f} \times m$

kf is constant for water and its value is 1.86

$\bigtriangleup t_{f} = 3 \times 1.86 \times 1.12$

$\bigtriangleup t_{f} = 6.2$

the freezing point of water decreases by 6.2 °c

therefore we can say that, the solution will have a higher boiling point and a lower freezing point

Another question on Chemistry

Chemistry, 21.06.2019 19:30

What are the percent by mass of copper in penny lab

Answers: 3

Answer

Chemistry, 21.06.2019 22:00

Match each object to its description: a. coma of a comet b. comet tail c. oort cloud haze surrounding a nucleus created by solar wind. hypothetical sphere around the solar system

Answers: 1

Answer

Chemistry, 21.06.2019 22:30

Embryos of different species look very similar, which shows that the organisms share a ancestor.

Answers: 1

Answer

Chemistry, 22.06.2019 05:30

Liv sheldon given the balanced equation for an organic reaction: c2h2 + 2cl2 → c2h2cl4 this reaction is best classified as *

Answers: 1

Answer

You know the right answer?

1. compared to carbon-14, what does the nuclide carbon-12 have less of?
a. protons
b. n...