When the pentaacetate anomer obtained in this reaction is heated with zncl2 and acetic anhydride?

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When the pentaacetate anomer is heated with ZnCl2 and acetic anhydride, it is converted into the other anomer. Explain why it occurs.

If so, then the answer would be:

Glucose Pentaacetate is prepared through the acetylation of glucose with acetic anhydride.

Alpha-anomer is produced when acidic catalyst is present like zinc chloride. On the other hand, beta-anomer is formed when a basic catalyst is present, like sodium acetate.

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explanation:

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1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: