What volume of o2 at 874 mmhg and 33 ∘c is required to synthesize 18.0 mol of no?

490.93 liters is required to synthesize 18.0 mol of NO

Stokiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc.

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

In the reaction there are also manifestations of reagent substances namely gas (g), liquid (liquid / l), solid (solid / s) and solution (aqueous / aq).

Reactions that occur:

4NH₃ (g) + 5O₂ (g) -> 4NO (g) + 6H₂O (g)

Comparison of coefficient = mole ratio

So that mole O₂ = 5/4 x mol NO

mole O₂ = 5/4 x 18

mole O₂ = 22.5

To find the volume, assuming the ideal gas, we use the formula:

P = 874 mmhg = 874/760 mmhg = 1.15 atm

R = 0.082 L atm / mole K

T = 33 + 273 = 306 K

V = nRT / P

V = 22.5 0.082.306 / 1.15

V = 490.93 liters

the ideal gas law

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excess reactant

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the percentage yield

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limiting reactant

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Keywords: ideal gas law, mole, NO, O₂

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