Oxygen has a density of 1.43 g/l at stp. what is the density of oxygen at 1.30 atm?

Explanation:

It is given that pressure is 1.30 atm.

So, at STP temperature will be 273.15 K. And, according to the ideal gas equation:

                         PV = nRT ........ (1)

And,    Density =

or,               Volume = ....... (2)

Putting equation (2) is equation (1) we get the following.

                                 PV = nRT

Molar mass of oxygen is 32 g/mol. Now, putting the given values into the above equation to calculate density as follows.

                    Density =   g/L

                                  = 1.855 g/L

Thus, we can conclude that density of oxygen at 1.30 atm is 1.855 g/L.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2