Based on the sign of e°cell, classify these reactions as product favored or reactant favored as written. assume standard conditions. use these data.

I have notice that this problem doesn't provide the data to be used in solving it. But I found the same problem and found a data to be used in classifying it. This are the following 

Ni^2+ (aq) + S^2- (aq) > + Ni (s) S (s) 
Pb^2+ (aq) +H2 (g) > Pb (s) +2H^+ (aq) 
2Ag^+ (aq) + Cr(s) ---> 2 Ag (s) +Cr^2+ (aq)  

Solution

1. Ni2+ +2e-  => Ni . . Eo = -0.23 V
 . . S2- => S + 2e-  . . Eo = +0.51 V

 Ni2+ + S2-  => Ni + S . . Eo = +0.28 V .        if a positive Eo = a Spontaneous Reaction 

2. Pb2+ = 2e- => Pb . .Eo = -0.126 V 
. . . H2 ==> 2H+ + 2e- . . .Eo = +0.00 V 

Pb2+ + H2 ==> Pb + 2H+ .Eo = -0.126 V ...    a negative Eo = NONSPONTANEOUS 

(3) 2Ag+ + 2e- =>2 Ag . .Eo = +0.80 V 
. . .Cr ==> Cr2+ + 2e- . . . .Eo = +0.56 V 

2Ag+ + Cr ==> 2Ag + Cr2+ . .Eo = +1.36 V ... a positive Eo=  SPONTANEOUS

Ch4 and ph3 are both covalent since they are composed both of non-metals.    ch4 is non- polar because of  london forces and has a geometry of tetrahedral  ph3 , on the other hand, is umbrella shaped polar and has dipole-dipole intermolecular force (imf) . since ph3 is polar, it has a stronger imf