How many grams of hcl would be required to make 0.3 l of a 12.0 m solution?
a.25 g
b.146 g
c.131 g
d.40 g

The mass of HCl is 131 grams (option C)

Explanation:

Step 1: Data given

Volume of solution = 0.3L

Molarity = 12.0 M

Molar mass of HCl = 36.46 g/mol

Step 2: Calculate moles HCl

Moles HCl = molarity * volume

Moles HCl = 12.0 M * 0.3L

Moles HCl = 3.6 moles

Step 3: Calculate mass of HCl

Mass HCl =moles HCl * molar mass HCl

Mass HCl = 3.6 moles * 36.46 g/mol

Mass HCl = 131.3 grams ≈ 131 grams

The mass of HCl is 131 grams (option C)

possibly, yes.

explanation:

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i believe the answer is three water molecules