What is the equilibrium constant of pure water at 25°c? 1014 10–14 10–7 107

The equilibrium constant of pure water at  is

Further Explanation:

Equilibrium constant:

It determines the relationship between the reactants and products of the reaction. It is usually denoted by K. The equilibrium constant of water is represented by .

The self-ionization of water occurs as follows:

The expression to calculate  is as follows:

                                                     (1)

Here,

is the equilibrium constant of water.

is the hydrogen ion concentration.

is the hydroxide ion concentration.

The formula to calculate pH is as follows:

       (2)

On rearranging equation (2), we get:

             (3)

Pure water is neutral at  so its pH is 7.

Substitute 7 for pH in equation (3)

One mole of water ionizes to form one mole of  and one mole of . Therefore  is also .

Substitute  for both and in equation (1).

So the equilibrium constant of water is  

Learn more:

1. The reason for the acidity of water

2. Reason for the acidic and basic nature of amino acid.

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Equilibrium

Keywords: pure water, 25oC, equilibrium constant, pH, neutral, H+, OH-, 10-14, 10-7, neutral, 7, hydrogen ion concentration, hydroxide ion concentration.

the awnser is group 12