Ka of 0.0400 m solution of hclo2, ph = 1.80

The Ka is 0.0104.

To solve for the Ka, the formula is Ka = [H+][ClO-]/[HClO]. In order to determine the value of H+, the formula is H+ = 10^-pH (the pH here is 1.80). This yields 0.015848931924611134. In the ICE table, since H+ is the same value as ClO, then the ClO is also 0.015848931924611134. The HClO is the 0.04 - 0.015848931924611134. Substituting the values to the earlier mentioned equation, the answer is 0.01040072606175673227903507631149 or simply, 0.0104.

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.

i believe the answer is 5,000