You have a cup of hot water and you dissolve as much salt in it as possible. you then put the cup into the refrigerator and you check it again after 24 hours. what would you notice when you checked the cup after 24 hours in the refrigerator? none of the salt would settle out of the water. some of the salt would settle out of the water. all of the salt would settle out of the water. the salt water would have changed colors.

Some of the salt would settle out of the water.

Explanation:

This is an example of a supersaturated solution.

In this example, the salt is the analyte, and the water is the solvent.

When you mix the salt into the water in an ambient temperature there is a point where you can't solve more salt, because the amount of water isn't able to solubilize any more quantity of analyte. This is named supersaturation point.

If you expose the mix to the heat, the energy supply to the solution make that the excess of salt can be solubilized, but this effect only last until the heat still going on.

So when you put the solution into the refrigerator, the quick down of the heat makes that the excess of salt settles out of the water.

And all this process occurs because the solution always wants to reach the equilibrium between the analyte and the solvent.

the grams   of   barium that   are in   2.3 x 10^23   atoms of barium   is   52.4 g (answer c)

    calculation

mass = moles   of ba   x molar   mass of ba

  molar mass of ba from periodic table=   137.3 g/mol

  use the   avogadro's law   constant   to   calculate the moles of barium

  that   is     1 mole =   6.02   x 10^23 atoms

                    ? moles = 2.3 x 10^23   atoms

by cross   multiplication

=(1 mole   x 2.3x 10^23 atoms)   / 6.02   x10^23 atoms)=   0.382   moles

mass   is therefore = 137.3   g/mol x 0.382 mol = 52.4 ( answer c)

explanation:

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g