Acertain vinegar is 6.02% acetic acid (hc2h3o2, by mass. how many grams of acetic acid are contained in a 355 ml bottle of vinegar. assume a density of 1.01 g/ml.

First, determine the amount of vinegar in grams by multiplying the volume by the density. That is,
                                        mass = (355 ml) x (1.01 g/mL) = 358.55 g
Then, multiply the calculated mass above by the decimal equivalent of the given percentage above. 
                      amount of acetic acid = (358.55 g)(0.0602) = 21.58 g

Hno3(aq) → h+(aq) + no3−(aq). picture ii best represents the strong acid hno3. strong acids are strong electrolytes