Solid lithium and iodine gas are formed by decomposition of solid lithium iodide. write a balanced chemical equation for this reaction.

This was already asked and @andriansp answered it so here it is again:

"Lithium Iodide is LiO

Lithium is  Li

Iodine is I

Lithium will decompose to Li and I2, which means  :
2Li(s) + I2(g) ---> 2Lil(s)"

What are the options? i can you if you give them.

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃  → 3 nicl₂ + 2 albarium and copper bromideba + cubr  →  no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al  → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn  → znso₄ + na