How much 6.0 m hno3 is needed to neutralize 39 ml of 2.0 m koh?

Answer : The volume of needed are, 0.013 L

Explanation :

According to the neutralization law,

where,

= molarity of = 6.0 M = 6.0 mole/L

= molarity of = 2.0 M = 2.0 mole/L

= volume of = ?

= volume of = 39 ml = 0.039 L

conversion : 1 L = 1000 ml

Now put all the given values in the above formula, we get the volume of

Therefore, the volume of needed are, 0.013 L

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explanation:

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