What is the molecular formula for a compound if it is 39.99% carbon, 6.73% hydrogen, and 53.28% oxygen, and has a molar mass of 180.18 g/mol?

If molar mass of compound is 180.18 g/mol and of that mass 39.99 % is Carbon
     ∴ molar mass of carbon in compound = 180.18 g/mol × (39.99 ÷ 100)
                                                                 = 72 g/mol
        since a single carbon = 12 g/mol
        then number of carbons in compound = 72 ÷ 12 g/mol
                                                                    = 6 CARBON atoms

If molar mass of compound is 180.18 g/mol and of that mass 6.73 % is hydrogen
     ∴ molar mass of hydrogen in compound = 180.18 g/mol × (6.73 ÷ 100)
                                                                     ≈ 12 g/mol
        since a single hydrogen = 1 g/mol
        then number of hydrogen in compound = 12 ÷ 1 g/mol
                                                                    = 12 HYDROGEN atoms

If molar mass of compound is 180.18 g/mol and of that mass 53.28 % is Oxygen
     ∴ molar mass of oxygen in compound = 180.18 g/mol × (53.28 ÷ 100)
                                                                 ≈ 96 g/mol
        since a single oxygen= 16 g/mol
        then number of oxygen in compound = 96 ÷ 16 g/mol
                                                                    = 6 OXYGEN atoms

∴ molecular formula of compound (aldehexose sugar e.g. glucose) = C₆H₁₂O₆

Ibelieve your answer is true