What quantity, in grams, of methanol, ch3oh, is required to prepare a 0.244 m solution in 400. g of water?

3.1213 g of methanol will required to  prepare 0.244 m of solution in 400 g of water.

Explanation;

Let the mass of methanol be x

Mass of the solvent = 400 g= 0,4 kg

1 kg = 1000 g

Molality of solution = 0.244 m

Molality=

3.1213 g of methanol will required to  prepare 0.244 m of solution in 400 g of water.

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explanation:

answer : a model is often used to explain and make things easier to understand when any scientific topic needs to be demonstrated and explained.

as in this case where a scientist wants to use a model to present the results of his detailed scientific investigation. he should do it as it will him to make the audience understand the concept in a much better way. also, it can be changed according to new scientific understandings.