Chemistry, 19.09.2019 01:00 fizz49

The common-ion effect is a consequence of
a. boyle s law.
c. avogadro s principle.
b. le ch telier s principle.
d. chemical kinetics.

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The answer is the option b. Le Chatelier's principle.

Le Chatelier's principle states that when chemical equilibrium is taken out of the equilibrium the reaction will shift to restore the equilibrium.

The common-ion efect is the addition of a solution that apports an ion that is already in the solution, which then will shift the reaction to reach a new equillibrium.

Answer from: Quest

In meteorology, a cloud is an aerosol consisting of a visible mass of minute liquid droplets, frozen crystals, or other particles suspended in the atmosphere of a planetary body. nephology is the science of clouds, which is undertaken in the cloud physics branch of meteorology.cirrus clouds usually describe clouds high in the atmosphere that can include wispy clouds, typically with ice crystals. variations include cirrus, cirrocumulus and cirrostratus as defined by the cloud's position in the atmosphere.layered stratus clouds have both flat tops and bases, and can appear as if they take up the whole sky, stretching from horizon to horizon. other combinations and variations include stratus, stratocumulus, nimbostratus and altostratus.cumulus clouds often pile up in multiple layers of the atmosphere, representing clouds that develop vertically. cumulus clouds often look like pillars with anvil-type tops or columns of clouds stacked vertically. variations include cumulus, cumulus-congestus, cumulonimbus and altocumulus.

Answer from: Quest

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = $25^oc$ = 298 k $)0^oc=273kelvins$

$o_3+3no\rightarrow 3no_2,\delta h_{reaction}=? [/)</p><p>[tex]\delta h_{no}=90.4kj/mol$

$\delta h_{no_2}=33.85kj/mol$

$\delta h_{o_3}=142.2kj/mol$

$\delta h_{reaction}=\sum \delta h_{products}-\sum\delta h_{reactants}=3\times\delta h_{no_2}-(3\times \delta h_{no}+\delta h_{o_3})$

$\delta h_{reaction}=33.85-(90.4+142.2)=-311.85kj/mol$

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

$v_{no}=12.00 l,v_{o_3}=8.50 l$

$pv_{no}=n_{no}rt=1atm \times 12.00 l=n_{no}\times 0.0821 atml/k mol \times 298 k$

$n_{no}=0.49 moles$

$pv_{o_3}=n_{o_3}rt=1atm \times 8.50 l=n_{o_3}\times 0.0821 atml/k mol \times 298 k$

$n_{o_3}=0.34 moles$

according to reaction 3 moles no are reacting with 1 mol of $o_3$ ,then 0.49 mol of no will react with $\frac{1}{3}\times 0.49$ moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and $o_3$ is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

$\delta h_{reaction}\times \text{moles of no}=-311.85kj/mol\times 0.49 mol=-152.80kj/mol$

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The common-ion effect is a consequence of
a. boyle s law.
c. avogadro s principle.

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