How many liters of chlorine gas, at standard temperature and pressure, will react with 15.5 grams of potassium metal? show all of the work used to solve this problem. 2k + cl2 yields 2kcl

2K +Cl₂ --> 2KCl

First calculate how many moles we have of potassium.

15.5 g * (mol/39.0983 g) = 0.396 mol K

2 moles of K reacts with 1 mole of Cl₂, so we know we'll need 0.198 moles of Cl₂.

Standard temperature and pressure is 273.15 degrees K and 1 atm.

Using the gas law PV = nRT, with R = 0.0821 L*atm*K^-1 *mol^-1, you should be able to solve for V, volume, in Liters.

Hno3(aq) → h+(aq) + no3−(aq). picture ii best represents the strong acid hno3. strong acids are strong electrolytes

Aphysical change is one that you can put in and remove like a ham sandwich. the stuff you put in there can be changem its not permanet. a chemical change is on that can't be change thats permanet. like when you make a cake and bake it. you can't get those ingredients back.