A0.630 m aqueous solution of kbr has a total mass of 86.0 g. what masses of solute and solvent are present?

Solution :

Molality of the solution :  0.630 M

Mass of the KBr (solute) = x grams

Mass of the solvents : 86.0 - x grams

Mass of the solute = 6.001 grams

Mass of the solvent = 86.0 - x grams = 86.0 - 6.001 g = 79.999 grams

The mass of solute in 0.63 m KBr solution is 6.96 grams. The mass of the solvent has been 79.03 grams.

Molality can be defined as the mass of solute present in 1 kg of solvent.

Given, molality = 0.63 m

The total mass of solution = 86 g

Let the mass of solute = x

Mass of solvent = 86 - x

Molality =

0.63 =

x = 6.96 grams

Thus the mass of solute present in the solution is 6.96 grams.

Mass of solvent = 86 - the mass of solute

Mass of solvent = 86 - 6.96 grams

Mass of solvent = 79.03 grams

For more information about molality, refer to the link:

link

specific gravity is the density of a substance divided by the density of water. since (at standard temperature and pressure) water has a density of 1 gram/cm3, and since all of the units cancel, specific gravity is usually very close to the same value as density

so "c" is the answer

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the temperature of the gas, in k, not celsius.