Chemistry, 29.01.2020 02:49 selenaK9514

14.0g n2 react with 3.15g h2 to give an actual yield of 14.5 nh3

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You can determine the limiting reactant and the percentaje yield as follow.

1) State the equation that represents the chemical reaction

N2 (g) + 3H2 (g) → 2NH3 (g)

molar ratios: 1 mol N2 : 3 mol H2 : 2 mol NH3

2) Convert the two masses to moles by dividing each by its molar mass

14.0 g N2 / 28 g/mol = 0.5 mol

3.15 g H2 / 2g/mol = 1.575 mol

Proportion = 0.5 mol N2 / 1.575 mol H2 = 0.317 mol N2 / mol H2

3) Given that the theoretical ratio 1 / 3 > actual proportion 0.317 , the H2 is the limiting reactant (it will be consumed and yet some moles of N2 will remain without reacting).

4) Percentage yield = actual yield * 100 / theoretical yield

Theoretical yield = [ 2 mole NH3 * 1 mole N2 ] * 0.5 mol N2 = 1 mole NH3

actual yield = 14.5 g NH3 / molar mass NH3 = 14.5 g / 17 g/mol = 0.853 mol

Percentage yield = actual yield * 100 / theoretical yield = 0.853 mol * 100 / 1 mol = 85.3%

85.3%

Answer from: Quest

If it releases 5 tons a day and there are 7 days a take that answer and multiply by 5 percent (0.05) to find the amount released in one week. leave a comment if you need more .

Answer from: Quest

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.

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14.0g n2 react with 3.15g h2 to give an actual yield of 14.5 nh3...