A100.0-g bar of gold is heated from 25 ∘c to 50 ∘c during which it absorbs 322 j of heat. assume the volume of the gold bar remains constant. calculate the specific heat of gold

We can use the heat equation,

Q = mcΔT

Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).

Q = 322 J

m = 100.0 g

c = ?

ΔT = (50 - 25) °C = 25 °C

By applying the formula,

   322 J = 100.0 g x c x 25 °C

          c = 322 J / (100.0 g x 25 °C)

          c = 0.1288 J g⁻¹ °C⁻¹

Hence, the specific heat of gold is 0.1288 J g⁻¹ °C⁻¹.

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