Given 4.8 moles of a gas in a 1.8 l container, if the temperature is found to be 31 degrees celsius, what is the pressure of the gas? (the ideal gas constant is 0.0821 l · atm/mol · k and 1 atm = 760 torr.)
6.79 torr
66.55 torr
6.79 x 100 atm
6.66 x 101 atm

Answer : The pressure of the gas is,

Solution :

Using ideal gas equation,

where,

n = number of moles of gas  = 4.8 moles

P = pressure of the gas = ?

T = temperature of the gas =

R = gas constant = 0.0821 Latm/moleK

V = volume of gas = 1.8 L

Now put all the given values in the above equation, we get the pressure of the gas.

Therefore, the pressure of the gas is,

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"