What is the molarity of a solution that contains 85.0 grams of na2so4 in 325 milliliters of solution? (the mass of one mole of na2so4 is 142 grams.)
0.195 m
0.599 m
1.84 m
6.22 m

Answer : The molarity of a solution is, 1.84 M

Explanation : Given,

Mass of = 85.0 g

Molar mass of = 142 g/mole

Volume of solution = 325 ml

Molarity : It is defined as the number of moles of solute present in one liter of solution.

In this question, the solute is .

Formula used :

where,

= mass of solute

= molar mass of solute

= volume of solution in ml

Now put all the given values in the above formula, we get the molarity of the solution.

Therefore, the molarity of the solution is, 1.84 M

the volume increases

a polar bond is formed when electrons are shared unevenly between atoms