How many atoms of phosphorus are represented in 2ca3(po4)2?

2Ca₃(PO₄)₂ contains 2 moles of phosphorus per mole, and there are 2 moles present. Therefore, there are a total of 4 moles of phosphorus present. Each mole contains 6.02 x 10²³ atoms. The atoms of phosphorus are:
6.02 x 10²³ x 4
= 2.408 x 10²⁴ atoms