When 10 grams of copper and 10 grams of iodine are mixed, what is the
theoretical yield of copper i iodide?
2cu + i2 → 2cui

30 grams

15 grams

7.5 grams

20 grams

Third option is correct, 7.5 grams of CuI.

Given data :

Mass of copper = 10 grams

Mass of iodine = 10 grams

theoretical yield of copper iodide = ?

Solution:

Moles of Cu: 10 / 63.5 = 0.157 mol.

Moles of I2: 10 / 254 = 0.039 mol.

Equation : 2Cu + I2 → 2CuI

Limiting reactant : I2

So Moles of CuI produced =  0.039 mol.

Mass of CuI = 0.039 mol * 190.5 = around 7.5g

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