To form a hydrogen bond, what must the non-hydrogen atom ( n , o , or f ) involved in the bond possess?

Explanation:

As atomic number of hydrogen is 1. So, it needs to gain one electron from a donor atom in order to become stable in nature.

Therefore, when a hydrogen bond is formed with a non-hydrogen atom then there must be presence of a non-bonding electron.

For example, atomic number of nitrogen atom is 7 and its electronic distribution is 2, 5.

Here, three electrons are needed by a nitrogen atom. And, when three nitrogen atoms get attached to a nitrogen atom then a compound is formed.

Thus, we can conclude that to form a hydrogen bond, the non-hydrogen atom ( N , O , or F ) involved in the bond must possess a non-bonding electron pair.

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

o conteúdo de calor de um sistema é igual à entalpia apenas para um sistema que é constante