How many grams of nacl will be produced when 2235 g of hcl are neutralized by an excess of naoh according to the equation below?
( hcl + naoh = h2o + nacl )

Convert the Mass of HCl to Moles. 2235g HCl*(1mol/36.461)= 61.29 mols HCl.

With that number in mind, we can look at the equation and see that the molar ratio (based on the coefficients) for HCl to NaCl is 1:1. So, when 61.29 mols of HCl is used, 61.29 mols of NaCl will be produced. 

Convert 61.29 mols of NaCl back into grams.. 61.20 mols*(58.4428g/1mol)

answerL 3,582.44859 g NaCl. 

Hope this helps with learning the process!

A1 a 2 a 3 ooh lol i think that's it