In the following reaction, how many grams of ammonia (nh3) will react with 27.8 grams of nitric oxide (no)? 4nh3 + 6no → 5n2 + 6h2o the molar mass of ammonia is 17.0337 grams and that of nitric oxide is 30.01 grams.
a- 23.7 grams
b- 10.5 grams
c- 73.5 grams
d- 32.7 grams

4NH₃ + 6NO → 5N₂ + 6H₂O

mol of NO  =  
 
                  =  
                   
                  =  0.93 mol

Based on the balance equation mole ratio of NH₃  :  NO  is   4 : 6
                                                                                            =  2 : 3

If mol  of NO  =  0.93 mol

then mol of NH₃ = 
                           
                          =  0.62 mol

Mass of ammonia =  mol  ×  molar mass
          
                             =  0.62 mol   ×  17.03 g/mol
 
                             =  10.54 g

Therefore B is the best answer

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