The fuel used in many disposable lighters is liquid butane, c4h10. butane has a molecular weight of 58.1 grams in one mole. how many carbon atoms are in 2.50 g of butane?

Do you have 1,04 ×10²³ carbon atoms in 2,50g of butane.

Explanation:

2,50 g  ₓ ( 1 mol butane / 58,1 g ) = 0,043 moles of butane

0,043 moles of butane × ( 6,022×10²³ molecules / 1 mol ) =

2,59 ×10²² molecules of butane

2,59 ₓ 10 ²² molecules of butane ( 4 carbon atoms / 1 molecule of butane ) =

1,04 ×10²³ carbon atoms

I hope it helps!

1 is the answer to this problem

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