An iron atom has a mass of ×9.2710−23g and a cooking pot has a mass of 0.500kg

Missing question: Use this information to answer the questions below. Be sure your answers have the correct number of significant digits. What is the mass of 1 mole of iron atoms?  Round your answer to 3 significant digits. How many moles of iron atoms have a mass equal to the mass of a cooking pot? Round your answer to 3 significant digits.

1) m(Fe) = 9.27·10⁻²³ g; mass of iron atom.

M(Fe) = m(Fe) · Na (Avogadro constant).

M(Fe) = 9.27·10⁻²³ g · 6.022·10²³ 1/mol.

M(Fe) = 55.823 g/mol; mass of one mole of iron atoms.

2) m(cooking pot) = 0.500 kg.

m(cooking pot) = 0.5 kg · 1000 g/kg.

m(cooking pot) = 500 g.

n(Fe) = m(cooking pot) ÷ M(Fe).

n(Fe) = 500 g ÷ 55.823 g/mol.

n(Fe) = 8.957 mol; amount of iron atoms.

a saline water is fed to a reverse osmosis unit at flow rate o rotameter connected to reject (retentate) line reads 8 installed in reject and permeate line reads 15.2 milli siemens/cm and 300 micro siemens/com respectively.