How many grams of chlorine gas must react to give 4.82g of bicl3?
2bi(s)+3cl2(
g.→2bicl3(s) my answer was wrong/ review and tell me where i went wrong.
4.82g bicl3*1mol bicl3/215.33g bicl3*3 mol cl2/2 mol bicl3* 70.9g cl2/1 mol cl2=6.50 g cl2

Smog is the term used to describe the combination of fog and smoke

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Which statement can best be concluded from the ideal gas law?