How many grams of n2 must react to form 1.7 grams of ammonia, nh3?

The correct answer is 1.4g of nitrogen.

Explanation:

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The reaction to

creating ammonia from nitrogen is:

N2 (g) + 3H2 ---> 2NH3 (g)

NH3 mass = 1.7 g

N2 = 28g / mol

NH3 = 17g / mol

each one mole of nitrogen we obtain two moles of ammonia, then:

mass N2 = 1.7g * (28g / mol / 17g / mol) = 1.4g

We conclude that the correct answer is 1.4g of nitrogen.

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