100.-gram sample of h2o() at 22.0°c absorbs 8360 joules of heat. what will be the final temperature of the water?

Final Temperature =  41.9°C

Explanation:

Mass = 100g

Initial Temperature (T1) = 22°C

Final Temperature (T2) = ?

Heat = 8360

Formular relating these parameters is given as;

H = MC(T2-T1)

Where C = Specific Heat Capacity of water = 4.2 J/g°C

Inserting the values, we have;

8360 = 100 * 4.2 * (T2 - 22)

T2 - T1 = 8360 / 420

T2 - T1 = 19.9

T2 = T1 + 19.9

T2 = 22 + 19.9

T2 = 41.9°C

some sources quote the lethal dose, for an average 170lbs opiate-naive individual is between 75 and 375 mg