Assuming 100% dissociation, calculate the freezing point and boiling point of a 2.5 m sncl4 (aq)

The freezing point of the solution is 249.75 K and boiling point of the solution is 379.4 K.

Explanation :

Molality of = 2.5

a) Depression in freezing point:

i = Van'T Hoff factor =  5 (for 100% dissociation)

= freezing point constant= 1.86Kkg/mol

The freezing point of the solution is .

b) Elevation in boiling point:

i = Van'T Hoff factor =  5 (for 100% dissociation)

=boiling point constant= 0.512 Kkg/mol

The boiling point of the solution is .

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-