Identify the limiting reagent and the volume of co2 formed when 11l cs2 reacts with 18l o2 to produce co2 gas?
and so2 gas at stp.

cs2 (g) + 3o2(> co2(g) +2so2(g)

a.) o2; 6.0 l co2
b.)cs2; 11 l co2
c.) cs2; 5.5 l co2
d.) o2; 27 l co2

The correct answer is option a) O2; 6.0 L C02

Explanation:

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

Then, taking into account that the reaction occurs under STP conditions, it is possible to determine the amount of moles of CS2 and O2 that react, with volumes 11L and 18L respectively. This determination is made by a rule of three:  

moles of CS2=0.49

moles of O2=0.80

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use the reaction stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), and the amount of moles calculated previously. You can use a simple rule of three as follows: if by stoichiometry one mole of CS2 reacts with 3 moles of O2, how much moles of O2 will be needed if 0.49 moles of CS2 react?

moles of O2=1.47

But 1.47 moles of O2 are not available, 0.80 moles are available. Since you have less moles than you need to react with 0.49 moles of CS2, oxygen O2 will be the limiting reagent.

Then, it is possible to determine the amount of moles of CO2 produced by another rule of three: if by stoichiometry 3 moles of O2 produce 1 mole of CO2, how many moles of CO2 will be formed if 0.80 moles of O2 react?

moles of CO2=0.27

Finally, taking into account the previously stated STP conditions and the amount of moles of CO2 formed, it is possible to determine the volume of CO2 that is formed by a rule of three: if 1 mole occupies 22.4 L, how much volume occupies 0.27 moles?

Volume of CO2=6.048 L  ≅ 6.0 L

 So, the correct answer is option a) O2; 6.0 L C02

assuming that your periodic table has eighteen columns, you should highlight   the four elements in the third column from the left of the table.

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the have energy higher than those in the orbital while lower than those of the orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the orbital is therefore filled right after orbitals and before orbitals.  

potassium has electron configuration and calcium . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the and should be highlighted as well.