Jose and gina are studying balanced and unbalanced forces and are challenged to test their theories. predict the result when jose applies 6 newtons of forces to one side of a box and gina applies 6 newtons of force to the other side of the box.

a)
the box does not move.

b)
the box moves toward gina.

c)
the box moves toward jose.

d)
the force crumples the box.

Answer : The correct option is, (A) The box does not move.

Explanation :

Force : It is defined as the force can be a push or a pull.

Balanced force : When the two forces are equal in magnitude and in opposite direction. These forces are balance to each other. In this force, the object does not move.

Unbalanced force : When the two forces are not equal in magnitude and direction. These forces does not balance to each other. In this force, the object will move on that side where the force will be applied more.

There are three cases :

Case 1 :

That means, when the force applied from left side are equal to the force applied from the right side then they balance to each other and object will not move.

Case 2 :

That means, when the force applied from left side are more than the force applied from the right side then the object will move towards right side.

Case 3 :

That means, when the force applied from left side are less than the force applied from the right side then the object will move towards left side.

According to question, the applied forces are equal in magnitude and in opposite direction. So, the box will not move.

Therefore, the correct answer is, A

part 1: the half-life of the element is 22 years.

part 2: it will take 132.02 year for the sample to decay from 308.0 g to 4.8125 g.

explanation:

part 1: there are two ways to determine the half life time.

first way: the half life time can be determined directly from its definition as it is the time required for the sample to decay to its half concentration.

from the data the initial concentration was 45.0 g and decayed to its half value (22.5 g) in 22.0 years.

second way: the radio active decay is considered first order reaction so we can use the laws of first order reactions.

k = (1/t) ln (a/a-x), where k is the rate constant of the reaction,

t is the time of the reaction

a is the initial concentration of the reactant

a-x is the remaining concentration at time (t)

a = 45.0 g the initial concentration at t = 0 year.

at t = 22 year, a-x = 22.5 g

then k = (1/22 year) ln (45.0 g/ 22.5 g) = 0.0315 year-1.

the half-life time (t1/2) = ln 2/ k = 0.693/ k =0.693/ 0.0315 = 22 years.

part 2:

using the same law k = (1/t) ln (a/a-x),

using the given data; a = 308.0 g and a-x = 4.8125 g and the calculated k from the part 1 (k = 0.0315 year-1)

t = (1/k) ln (a/a-x) = (1/0.0315) ln (308.0/ 4.8125) = 132.02 years

they are both synthetic elements

explanation:

d