In the reaction k2cro4 (aq) + pbcl2 (aq) 2kcl (aq) + pbcro4(s), how many grams of pbcro4 will precipitate out from the reaction between 25.0 milliliters of 3.0 m k2cro4 in an excess of pbcl2?

Reaction equation:
K₂CrO₄(aq) + PbCl₂(aq) → 2KCl(aq) + PbCrO₄(s)

Concentration = moles / Liter
moles(K₂CrO₄) = 3 x 0.025
= 0.075

By the equation, we see that the molar ratio of
K₂CrO₄ : PbCrO₄ is
1 : 1
moles(PbCrO₄) = 0.075

mass = moles x Mr
mass = 0.075 x (207 + 52 + 16 x 4)

mass = 24.2 grams

Ithink the answer is 56.