What volume will 0.875 moles of kr occupy at stp?

               Volume =  19.6 L

                     As we know that one mole of any Ideal gas at standard temperature and pressure occupies exactly 22.4 dm³ volume.

Using this reference, we can calculate the volume occupied by Krypton (Ideal situation) as,

                     1 mole of Kr occupies  =  22.4 L of Volume

So,

                  0.875 moles of Kr will occupy  = X L of Volume

Solving for X,

                       X =  (0.875 mol × 22.4 L) ÷ 1 mol

                      X =  19.6 L