A reaction has a rate of 0.026g/s. This was established from measuring the mass lost from a sample of calcium carbonate across three and a half days. If the sample of calcium carbonate had a mass of
581kg at the beginning of the reaction, what was its mass at the end?
ANSWER PLZZZ ​

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

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