During the Viking landings on Mars, the atmospheric pressure was determined to be on the average about 6.50 millibars (1 bar = 0.987 atm). What is that pressure in torr and kPa?

The pressure is equal to 4.87 torr and 0.649 kPa.

Explanation:

The atmospheric pressure was determined to be on the average about 6.50 millibars.

As 1 bar = 0.987 atm

6.5 mbar = 0.0065 bar

So,

0.0065 bar = (0.0065×0.987 ) atm

= 0.0064155  atm

Since, 1 atm = 760 torr

So, 0.0064155  atm = 4.87 torr

Since, 1 torr = 133.322 Pa

4.87 torr = 649.27 pa

or

4.87 torr = 0.649 kPa

Hence, the required pressure is equal to 4.87 torr and 0.649 kPa.

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )

i think that the answer is c