P4O10 + 6H20 → 4H3PO4 If 30 g of H2O reacts with 40g of P4O10, what is the limiting reactant? How much H3PO4 can be formed?

  is the limiting reagent

66.6 g of will be formed.

Explanation:

To calculate the moles :

According to stoichiometry :

1 mole of require 6 moles of

Thus 0.14 moles of will require=  of

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

As 1 mole of give = 4 moles of

Thus 0.17 moles of give =  of

Mass of

Thus 66.6 g of will be formed.