Ice at 0.0 degrees C is combined with 50.0g of water at 75.0 degrees C. Calculate the grams of ice present initially if the entire mixture comes to a final temperature of 25.0 degrees C after the ice melts. Specific heat of water is 4.18 J/goC. SHOW WORK!

mi = 31.28 g

Explanation:

According to the law of conservation of energy:

where,

mi = mass of ice = ?

L = Latent heat of fusion of ice = 334 J/g

mw =  mass of water = 50 g

C = specific heat of water = 4.18 J/g.°C

ΔT = change in temperature of water = 75°C - 25°C = 50°C

Therefore,

mi = 31.28 g

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a. energy is absorbed in the reaction.

if in a given reaction the energy of products is greater than the energy of reactants it means that reaction is endothermic and during the reaction, the energy is absorbed by reactants. in an endothermic reaction, the products have more stored chemical energy than the reactants. and in this reaction the reactants are more stable than products before the compounds with less energy are always more stable.