pb(No3)2(aq) +2KCI(aq)---PbCl2(s)+KNO2(aq). how many grams of PbCl2 solution will react with a 0.46 L of a 0.101m KCI solution​

The answer would be c. fish

Radon-222 or rn-222 has a half-life of 3.82 days. to determine the fraction of an original sample of rn-222 that remains unchanged after 7.646 days, we calculate the amount of rn-222 remaining after 7.646 days and divide it with the original amount. using 1 gram as a basis and using half-life calculation methods, we can determine that  0.249 or 0.25  grams of rn-222 will remain, and thus the fraction remaining is 0.25 or 1/4.

It starts to rust i think