Raiderium is 74.655% Cv, which has an atomic mass of 43.064 amu, 24.958% "Cv, which has a mass of 46.125 amu, and 0.387% C, which has an atomic mass of 47.982 amu. Please calculate the average atomic mass of Raiderium.

(0.00387 x 47.982)

Explanation:

(0.00387 x 47.982)

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

personal, she chose to do it.