You are performing a reaction involving the collection of a gas at SATP. If 5.00 g of magnesium is added to 100.0 cm3 of 0.100 mol dm−3 HCl, determine the volume of hydrogen gas that will be collected at SATP.

The volume of hydrogen produced is 0.122 L

Explanation:

To calculate the moles :

The balanced chemical equation is:

According to stoichiometry :

2 moles of require = 1 mole of

Thus 0.01 moles of will require=  of

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

As 2 moles of give = 1 mole of

Thus 0.01 moles of give =  of

According to ideal gas equation:

P = pressure of gas = 1.0 atm  (SATP)

V = Volume of gas = ?  

n = number of moles = 0.005

R = gas constant =

T =temperature = (SATP)

Thus volume of hydrogen produced is 0.122 L

- lead + phosphoric acid = hydrogen + lead(ii) phosphate