A weather balloon has a volume of 200.0 L at a pressure of 760 mm Hg. As it rises, the pressure decreases to 282 mm Hg. a. Will the volume of the balloon increase or decrease? Why?

b. What is the new volume of the balloon? (Assume constant temperature)

a. Increase

b. 539 L

Explanation:

Step 1: Given data

Step 2: Calculate the final volume of the gas

The pressure of the gas is inversely proportional to the volume. So, as the pressure decreases, the volume must increase. Assuming constant temperature and ideal behavior, we can calculate the final volume of the gas using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁/P₂

V₂ = 760 mmHg × 200.0 L/282 mmHg = 539 L

idk

explanation:

"hydrogen bonding is the attraction of h atoms in the water molecule (slight + charge) to o atoms in a neighboring water molecule (slight - charge); it is a weak interatomic force. but it is still strong enough to the water molecules "stick" together."