a 55g block of metal has a specific heat of 0.45 J/g°C. What will be the temperature change of this metal if 450 J of heat energy are added

Change in temperature (Δt) = 18.18°C (Approx.)

Explanation:

Given:

Mass of metal block (M) = 55g

Specific heat of metal (c) = 0.45 J/g°C

Amount of energy added (Q) = 450 J

Find:

Change in temperature (Δt)

Computation:

Using Specific Heat Energy formula

Q = McΔt

450 = (55)(0.45)(Δt)

450 = (24.75)(Δt)

Change in temperature (Δt) = 450 / 24.75

Change in temperature (Δt) = 18.18°C (Approx.)

43.452

step-by-step explanation:

284 times .153 = 43.452

the answer is 1260

you spend 7 hours in school for 1 school day with 5 school days in 1 school week with 36 school weeks in a school year.

7*5*36= 1260 it's all about multiplying