If 148.8 grams HCl reacts with excess Zn, how many moles of ZnCl2 could be formed? (Molar mass of HCI=36.46 g/mol)

2.04moles

Explanation:

The balanced chemical equation of this reaction is given as follows:

Zn + 2HCl → ZnCl2 + H2

Based on the above balanced equation, 2 moles of hydrochloric acid (HCl) reacts to produce 1 mole of Zinc chloride (ZnCl2).

The question states that 148.8 grams HCl reacts. We need to convert this value to mole by using the formula;

mole = mass/molar mass

Molar mass = 36.46g/lol

mole = 148.8/36.46

mole = 4.08moles of HCl

Hence, if 2 moles of hydrochloric acid (HCl) reacts to produce 1 mole of Zinc chloride (ZnCl2).

Then, 4.08moles of HCl will react to produce (4.08 × 1/2)

= 2.04moles of ZnCl2.

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