QUESTION 13 What is the boiling point of a 0.50 m aqueous solution of Al(NO 3) 3?
(The boiling point elevation constant for water is 0.512 °C/m.)
O a. 100.51 °c O b. 101.02 °c O C. 102.05 °C 0 d. 106.60 °C

b. 101.02°C

Explanation:

The elevation of boiling point in a solvent due the addition of a solute is a colligative property called Boiling point Elevation. The formula is:

ΔT = Kb*m*i

Where ΔT is change in boiling point

Kb is boilinig point elevation constant = 0.512°C/m for water

m is molality of the solution = 0.50m

And i is Van't Hoff Factor (4 for the Al(NO₃)₃ because its disolution produce 4 ions)

Replacing:

ΔT = 0.512°C/m*0.50m*4

ΔT = 1.02°C

As the boiling point of pure water is 100°C and the increasing is of 1.02°C, boiling point of the solution is:

101.02°C

Right option is:

i think it is d. e because the next one is igneous.

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."