If you want to make 174 grams of NiFz, how many moles of HF will you need, using the following balanced chemical equation? Ni + 2 HF - NiF2 + H2

3.6mol

Explanation:

The balanced chemical equation of this reaction is given as follows:

Ni + 2HF → NiF2 + H2

Based on the above equation, 2 moles of HF will react to produce 1 mole of NiF2.

According to this question, to make 174 grams of NiF2, we find the number of moles of HF required. However, we first convert the mass value of NiF2 to mole value using;

mole = mass/molar mass

Molar mass of NiF2 = 58.7 + 19(2)

= 58.7 + 38

= 96.7g/mol

mole = 174/96.7

mole = 1.799mol of NiF2

Hence, if 2 moles of HF will react to produce 1 mole of NiF2.

- 1.799mol of NiF2 will require (1.799 × 2) = 3.598

= 3.6mol of HF.

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-

where are the choice options?