Chemistry, 14.04.2021 03:30 devoncruz23
When 3.52 g of bismuth oxide (molar mass - 465.96 g/ml) reacts with excess carbon to form 2.91 g of bismuth metal (molar mass-208.98) according to the equation:
Bi2O3(s) + 3C(s) = 2 Bi(s) + 3 CO(g)
24
What is the percent yield of the reaction?
(Answer to 1 decimal place)
25
Answers: 3
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When 3.52 g of bismuth oxide (molar mass - 465.96 g/ml) reacts with excess carbon to form 2.91 g of...
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